Next closest time

Time: O(1); Space: O(1); medium

Given a time represented in the format “HH:MM”, form the next closest time by reusing the current digits.

There is no limit on how many times a digit can be reused.

You may assume the given input string is always valid.

For example, “01:34”, “12:09” are all valid. “1:34”, “12:9” are all invalid.

Example 1:

Input: time = “19:34”

Output: “19:39”

Explanation:

  • The next closest time choosing from digits 1, 9, 3, 4, is 19:39, which occurs 5 minutes later.

  • It is not 19:33, because this occurs 23 hours and 59 minutes later.

Example 2:

Input: time = “23:59”

Output: “22:22”

Explanation:

  • The next closest time choosing from digits 2, 3, 5, 9, is 22:22.

  • It may be assumed that the returned time is next day’s time since it is smaller than the input time numerically.

[1]:

class Solution1(object):
    def nextClosestTime(self, time):
        """
        :type time: str
        :rtype: str
        """
        h, m = time.split(":")
        curr = int(h) * 60 + int(m)
        result = None
        for i in range(curr+1, curr+1441):
            t = i % 1440
            h, m = t // 60, t % 60
            result = "%02d:%02d" % (h, m)
            if set(result) <= set(time):
                break
        return result

[2]:

s = Solution1()

time = "19:34"
assert s.nextClosestTime(time) == "19:39"

time = "23:59"
assert s.nextClosestTime(time) == "22:22"